Where to Travel » travel train http://www.where-to-travel.info Thu, 29 Jul 2010 09:05:22 +0000 http://wordpress.org/?v=2.9.2 en hourly 1 Euro Travel Secrets by Train, Part 2 http://www.where-to-travel.info/travel-train/euro-travel-secrets-by-train-part-2 http://www.where-to-travel.info/travel-train/euro-travel-secrets-by-train-part-2#comments Wed, 13 Jan 2010 11:15:03 +0000 admin http://www.where-to-travel.info/travel-train/euro-travel-secrets-by-train-part-2 Euro travel secrets for rail pass holders, part 2.

Duration : 0:5:48


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]]> http://www.where-to-travel.info/travel-train/euro-travel-secrets-by-train-part-2/feed 1 The Rocky Mountaineer: Canada Train Travel-Travel Video P http://www.where-to-travel.info/travel-train/the-rocky-mountaineer-canada-train-travel-travel-video-p http://www.where-to-travel.info/travel-train/the-rocky-mountaineer-canada-train-travel-travel-video-p#comments Sat, 09 Jan 2010 03:01:21 +0000 admin http://www.where-to-travel.info/travel-train/the-rocky-mountaineer-canada-train-travel-travel-video-p http://www.travelvideopostcard.com
Train Travel in Canada is the Rocky Mountaineer. Family Travel in Canada is Train Travel in Canada. Train travel on the Rocky Mountaineer starts in British Columbia, one of North America’s queen cities. Canada’s best travel is probably train travel. Traveling by train in Canada means Canada’s Rocky Mountaineer. Train Travel and Train Travel in Canada on the Rocky Mountaineer is luxury travel and train travel and train travel in Canada on the Rocky Mountaineer is train travel through the Canadian Rockies.
The Rocky Mountaineer Rail Tour is a two-day train trip in a glass bubble train making train travel through the Canadian Rockies a close and personal experience with beauty and nature.
Train Travel in Canada on Canada’s Rocky Mountaineer is luxury train travel luxury. Gourmet meals are served on the train. Drinks and elegant deserts too on this train travel trip on the Rocky Mountaineer train trip through the Rocky Mountains.
The Train travels through the Canadian Rockies and overnights in Kamloops, a cowboy town and adventure travel experience. The Train Travel in the Canadian Rockies ends in Calgary, the best Family Travel destination in Canada. Family Travel in Canada is Calgary.
Adventure and nature travelers love the beauty of the Rockies on Canada’s Rocky Mountaineer.

The Canadian Rockmountaineer is a two-day spectacular train ride from Vancouver in British Columbia through the Canadian Rockies in a glassed-in train. The train ride is a first class experience with elegant cuisine and dramatic nature.

Duration : 0:1:2


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]]> http://www.where-to-travel.info/travel-train/the-rocky-mountaineer-canada-train-travel-travel-video-p/feed 25 How long would it take a train to travel from St Louis to Kansas City in the late 1800’s? http://www.where-to-travel.info/travel-train/how-long-would-it-take-a-train-to-travel-from-st-louis-to-kansas-city-in-the-late-1800s-2 http://www.where-to-travel.info/travel-train/how-long-would-it-take-a-train-to-travel-from-st-louis-to-kansas-city-in-the-late-1800s-2#comments Tue, 05 Jan 2010 00:36:53 +0000 admin http://www.where-to-travel.info/travel-train/how-long-would-it-take-a-train-to-travel-from-st-louis-to-kansas-city-in-the-late-1800s-2 Note I am talking about train travel in the early west, not the present.

Which decade in the late 1800’s are you talking about?
Steam locomotives in the early west were laughed at..and in one famous demonstration in about 1840 or so, a horse beat a steam locomotive in a race. But as the "decades" went by, the technology improved and the trains got faster.
So a steam locomotive in the 1890’s was a lot more powerful and faster than the one back in 1860’s or 1870’s , for instance.

The average speed for steam locomotive in the late 1800’s probably was around 25-30 mph +/- 10mph.(I’m guessing)
Kansas city is about 250 miles away from St.Louis.
So the trip should take about 8-10 hours. That’s non-stop. Back in the day, trains make a lot of stops. That make the trip a lot longer.

]]> http://www.where-to-travel.info/travel-train/how-long-would-it-take-a-train-to-travel-from-st-louis-to-kansas-city-in-the-late-1800s-2/feed 1 Tokyo Travel Train Trip – Watch in HD -Test SONY HDR-HC9 http://www.where-to-travel.info/travel-train/tokyo-travel-train%ef%bb%bf-trip-watch-in-hd-test-sony-hdr-hc9 http://www.where-to-travel.info/travel-train/tokyo-travel-train%ef%bb%bf-trip-watch-in-hd-test-sony-hdr-hc9#comments Tue, 05 Jan 2010 00:32:28 +0000 admin http://www.where-to-travel.info/travel-train/tokyo-travel-train%ef%bb%bf-trip-watch-in-hd-test-sony-hdr-hc9 http://www.nicolechen.net

Tokyo
SONY HDR-HC9
Abit of color editing
Testing The feel.

Duration : 0:1:20


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]]> http://www.where-to-travel.info/travel-train/tokyo-travel-train%ef%bb%bf-trip-watch-in-hd-test-sony-hdr-hc9/feed 25 How long would it take a train to travel from St Louis to Kansas City in the late 1800’s? http://www.where-to-travel.info/travel-train/how-long-would-it-take-a-train-to-travel-from-st-louis-to-kansas-city-in-the-late-1800s http://www.where-to-travel.info/travel-train/how-long-would-it-take-a-train-to-travel-from-st-louis-to-kansas-city-in-the-late-1800s#comments Tue, 05 Jan 2010 00:28:18 +0000 admin http://www.where-to-travel.info/travel-train/how-long-would-it-take-a-train-to-travel-from-st-louis-to-kansas-city-in-the-late-1800s Note I am talking about train travel in the early west, not the present.

Which decade in the late 1800’s are you talking about?
Steam locomotives in the early west were laughed at..and in one famous demonstration in about 1840 or so, a horse beat a steam locomotive in a race. But as the "decades" went by, the technology improved and the trains got faster.
So a steam locomotive in the 1890’s was a lot more powerful and faster than the one back in 1860’s or 1870’s , for instance.

The average speed for steam locomotive in the late 1800’s probably was around 25-30 mph +/- 10mph.(I’m guessing)
Kansas city is about 250 miles away from St.Louis.
So the trip should take about 8-10 hours. That’s non-stop. Back in the day, trains make a lot of stops. That make the trip a lot longer.

]]> http://www.where-to-travel.info/travel-train/how-long-would-it-take-a-train-to-travel-from-st-louis-to-kansas-city-in-the-late-1800s/feed 0 Train travel …. Rocky Mountaineer through the Rockies http://www.where-to-travel.info/travel-train/train-travel-rocky-mountaineer-through-the-rockies http://www.where-to-travel.info/travel-train/train-travel-rocky-mountaineer-through-the-rockies#comments Wed, 30 Dec 2009 22:02:56 +0000 admin http://www.where-to-travel.info/travel-train/train-travel-rocky-mountaineer-through-the-rockies We raced the train and got ahead of it five times to get the video. Taking this train with observation cars and balconies through the Rocky Mountains is definitely on our list of things to do.

Duration : 0:5:36


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]]> http://www.where-to-travel.info/travel-train/train-travel-rocky-mountaineer-through-the-rockies/feed 7 How far will the train travel while it is stopping? http://www.where-to-travel.info/travel-train/how-far-will-the-train-travel-while-it-is-stopping http://www.where-to-travel.info/travel-train/how-far-will-the-train-travel-while-it-is-stopping#comments Wed, 30 Dec 2009 22:02:25 +0000 admin http://www.where-to-travel.info/travel-train/how-far-will-the-train-travel-while-it-is-stopping A train has a mass of 3.2*10^6 kg. What steady breaking force must be applied to the wheels of the train to bring it to a stop in 12 mins if it is initially traveling at a speed of 60 km/hr? How far will it travel while it is stopping?

I believe this is a frictionless problem…but I don’t know where to being with this problem.

Let:
m be the mass of the train,
a be its acceleration (negative for deceleration),
s be the stopping distance,
t be the stopping time,
F be the braking force,
u be the initial speed,
v be the final speed.

F = ma …(1)
v = u + at …(2)

60 km/hr = 60000 / 3600 = 50 / 3 m/s.
12 min = 720 sec.

Eliminating a from (1) and (2):
F = m(v – u) / t
= 3.2 * 10^6( 0 – 50 / 3) / 720
= – 7.41 * 10^4 N to 3 sig. fig.

F is negative as it is opposing the motion.

s = t(u + v) / 2
= 720(50 / 3 + 0) / 2
= 6000 m.

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